5k^2+48k+64=)

Solution for 5k^2+48k+64=) equation:

5k^2+48k+64=)

We move all terms to the left:

5k^2+48k+64-())=0

We add all the numbers together, and all the variables

5k^2+48k=0

a = 5; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·5·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*5}=\frac{-96}{10}
=-9+3/5
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*5}=\frac{0}{10}
=0
$